Tentukan interval nilai x yg memenuhi |3-x|=|2x-1|

|3-x|=|2x-1|

(3-x)²=(2x-1)²

(9 -6x +x²) = (4x² -4x +1)

(1-4)x² +(-6+4)x 9-1 =0

-3x² -2x +8 =0

(-3x +4 )(x + 2) =0

x = 4/3 dan x = -2