Matematika

Pertanyaan

tolong jawab ya
makasihh
tolong jawab ya makasihh

1 Jawaban

  • Misal :
    x + 1 = a
    y - 3 = b
    z + 2 = c

    Maka

    2/a + 2/b + 3/c = 2
    4/a + 3/b+ 3/c = 2
    ————————— —
    -2/a - 1/b = 0
    ————— *3
    -6/a - 3/b = 0..(pers.1)

    2/a + 2/b + 3/c = 2
    —————————— * 2
    4/a + 4/b + 6/c = 4
    -4/a + 1/b + 6/c = 5
    —————————— —
    8/a + 3/b = -1 (pers.2)

    Eliminasi pers 1 dan 2

    -6/a - 3/b = 0
    8/a + 3/b = -1
    ——————— +
    2/a = -1
    a = -2
    x + 1 = - 2
    x = -3

    Subs nilai a
    -6/a + 3/b = 0
    -6/-2 + 3/b = 0
    3/b = -3
    b = -1
    y-3 = -1
    y = 2

    Subs nilai a dan b :
    2/a + 2/b + 3/c = 2
    2/-2 + 2/-1 + 3/c = 2
    -1 - 2 + 3/c = 2
    3/c = 5
    c = 3/5
    z + 2 = 3/5
    z = 3/5 - 10/5
    z = -7/5

    HP = {(x,y,z)} = {(-3,2,-7/5)}