Asalamualaikum. teman saya butuh bantuan teman untuk mengerjakan materi fisika

Diket :
Gambar grafik fungsi posisi terhadap waktu,

Tanya :
Kecepatan rata-rata saat interval :
A. t1 = 0 sampai t2 = 2 sec
Lihat posisi saat :
t1 = 0 --> S1 = 0
t2 = 2 sec --> S2 = 10 m
Maka :
V = (S2 - S1)/(t2 - t1)
V = (10 - 0)/(2 - 0)
V = 10/2
V = 5 m/s

B. t1 = 0 sampai t2 = 4 sec
Lihat posisi di grafik
t1 = 0 --> S1 = 0
t2 = 4 sec --> S2 = 5 m
Maka :
V = (S2 - S1)/(t2 - t1)
V = (5 - 0)/(4 - 0)
V = 5/4
V = 1,25 m/s

C. t1 = 2 sec sampai t2 = 4 sec
Lihat posisi di grafik
t1 = 2 sec --> S1 = 10 m
t2 = 4 sec --> S2 = 5 m
Maka :
V = (S2 - S1)/(t2 - t1)
V = (5 - 10)/(4 - 2)
V = (- 5)/(2)
V = - 2,5 m/s

D. t1 = 4 sec sampai t2 = 7 sec
Lihat posisi di grafik
t1 = 4 sec --> S1 = 5 m
t2 = 7 sec --> S2 = - 5 m
Maka :
V = (S2 - S1)/(t2 - t1)
V = (- 5 - 5) / (7 - 4)
V = - 10/3
V = - 3,33 m/s

E. t1 = 0 sampai t2 = 8 sec
Lihat posisi pada grafik
t1 = 0 --> S1 = 0
t2 = 8 sec --> S2 = 0
Maka :
V = (S2 - S1)/(t2 - t1)
V = (0 - 0)/(8 - 0)
V = 0/8
V = 0

------
)|(
FZA