Fungsi f dinyatakan dengan rumus f(x) =px+q jika f(o) =-2 dan f(2)=4 tentukan f(5)

f(x) = px+q
f(0) = -2
f(2) = 4

f(0) = q
-2 = q
f(2) = 2p+q
4 = 2p-2
2p = 6
p = 3
Jadi,
f(5) = 3×5+(-2)
= 15-2
= 13