Matematika

Pertanyaan


1. jika {(x , y , z)} merupakan penyelesaian dari

x + 3y -z =13
3x + y -z =11
x + y - 3z =11
tolong di jawab pake caranya yah...

1 Jawaban

  • Materi : SPLTV
    Kelas : X SMA

    x + 3y - z = 13 ......... 1)
    3x + y - z = 11 .......... 2)
    x + y - 3z = 11 .......... 3)

    x + 3y - z = 13
    3x + y - z = 11
    ◆◆◆◆◆◆◆◆◆◆ [-]
    -2x + 2y = 2

    3x + y - z = 11 .... ×3
    x + y - 3z = 11 ...... ×1
    ◆◆◆◆◆◆◆◆◆◆◆◆◆◆
    9x + 3y - 3z = 33
    x + y - 3z = 11
    ◆◆◆◆◆◆◆◆◆◆◆◆◆[-]
    8x + 2y = 22

    -2x + 2y = 2
    8x + 2y = 22
    ◆◆◆◆◆◆◆◆◆◆ [-]
    -10x = -20
    x = 2

    8x + 2y = 22
    8(2) + 2y = 22
    16 + 2y = 22
    2y = 22 - 16
    2y = 6
    y = 3

    x + 3y - z = 13
    2 + 3(3) - z = 13
    2 + 9 - z = 13
    11 - z = 13
    -z = 13 - 11
    -z = 2
    z = -2

    Hp = { 2 , 3 , -2 }

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