Matematika

Pertanyaan

Carilah sudut vektor a =(-3,1,3) dan b =(3,3,2).

1 Jawaban

  • |a| = V(9+1+9) = V19
    |b| = V(9+9+4) = V22

    a.b = (-3)(3) + (1)(3) + (3)(2) = -9 + 3 + 6 = 0

    a.b = |a| |b| cos x
    0 = V19. V22 . cos x
    cos x = 0
    x = 90, x = 270

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