nilai sinus dari 105 derajat
Matematika
Hariyantkwon
Pertanyaan
nilai sinus dari 105 derajat
1 Jawaban
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1. Jawaban supaat69
[tex]
\sin{105\degree}\\
=\sin{\left(180\degree-75\degree\right)}\\
=\sin{75\degree}\\
=\sin{\left(30\degree+45\degree\right)}\\
=\sin{30\degree}\cos{45\degree}+\cos{30\degree}\sin{45\degree}\\
=\frac{1}{2}\cdot\frac{\sqrt{2}}{2}+\frac{\sqrt{3}}{2}\cdot\frac{\sqrt{2}}{2}\\
=\frac{\sqrt{2}}{4}+\frac{\sqrt{6}}{4}\\
=\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)
[/tex]