Tentukan persamaan garis yang diketahui: A.sejajar garis 3y-9x+1=0,melalui titik (-8,1) B.tegak lurus 2y-5x+7=0,melalui titik (5,-2)

A)
3y-9x+1 = 0
3y = 9x - 1
y = 3x - (1/3)
sejajar: m1 = m2 = 3
y = 3x + c
1 = 3(-8) + c
c = 1 + 24 = 25
y = 3x + 25
0 = y - 3x - 25

B)
2y - 5x + 7 = 0
2y = 5x - 7
y = (5/2)x - (7/2)
m1 = 5/2
m2 = -(1/m1) = -2/5
y = (-2/5)x + c
-2 = (-2/5)5 + c
-2 = -2 + c
c = 0
y = (-2/5)x
5y = -2x
0 = 5y + 2x