3log 2√2 + 3log 3√3 + 3log 36 / 3log 24 - 3log 4

[tex]
\frac{^3\log{2\sqrt{2}}+^3\log{3\sqrt{3}}+^3\log{36}}{^3\log{24}-^3\log{4}}\\
=\frac{^3\log{\left(2\sqrt{2}\cdot3\sqrt{3}\cdot36\right)}}{^3\log{\frac{24}{4}}}\\
=\frac{^3\log{6^{\frac{7}{2}}}}{^3\log{6}}\\
=^6\log{6^{\frac{7}{2}}}\\
=\frac{7}{2}\cdot^6\log{6}\\
=\frac{7}{2}\\
[/tex]