Matematika

Pertanyaan

cos 140-cos100/sin140-sin100
cos 140-cos100/sin140-sin100

1 Jawaban

  • [tex]
    \frac{\cos{140\degree}-\cos{100\degree}}{\sin{140\degree}-\sin{100\degree}}\\
    =\frac{-2\sin{\left(\frac{140\degree+100\degree}{2}\right)}\sin{\left(\frac{140\degree-100\degree}{2}\right)}}{2\cos{\left(\frac{140\degree+100\degree}{2}\right)}\sin{\left(\frac{140\degree-100\degree}{2}\right)}}\\
    =-\tan{120\degree}\\
    =-\tan{(180\degree-60\degree)}\\
    =\tan{60\degree}\\
    =\sqrt{3}\\
    [/tex]