Jika (1/32)^3-5x = 2 x 2^2 x 2^3 x ... x 2^20 maka nilai x =

[tex]
\left(\frac{1}{32}\right)^{3-5x}=2\cdot2^2\cdot2^3\cdot2^4\ldots\cdot2^20\\
\Leftrightarrow \left(2^{-5}\right)^{3-5x}=2^{1+2+3+\ldots+20}\\
\Leftrightarrow 2^{25x-15}=2^{\frac{20}{2}(1+20)}\\
\Rightarrow 25x-15=10\cdot21\\
\Leftrightarrow 25x=210+15\\
\Leftrightarrow x=9
[/tex]