persamaan linear tiga variabel x-y=1 x+z=-1 y-z=6 tolong yaaa

x - y = 1
x = y + 1

substitusi ke persamaan 2
x + z = -1
y + 1 + z = -1
y + z = -1 - 1
y + z = -2

eliminasi dengan persamaan 3
y + z = -2
y - z = 6
--------------- -
2z = -8
z = -8 / 2
z = -4

substitusi ke persamaan 2
x + z = -1
x + (-4) = -1
x = -1 + 4
x = 3

substitusi ke persamaan 1
x - y = 1
3 - y = 1
-y = 1 - 3
-y = -2
y = 2

maka
x = 3
y = 2
z = -4

Materi : SPLTV

x - y = 1
x + z = -1
◆◆◆◆◆◆◆ [-]
-y - z = 2

-y - z = 2
y - z = 6
◆◆◆◆◆◆◆ [-]
-2y = -4
y = 2

y- z = 6
2 - z = 6
-z = 6 -2
-z = 4
z = -4

x - y = 1
x - 2 = 1
x = 1 + 2
x = 3

Hp = {3, 2 , -4 }